2x^2+10x-25/4x+28

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Solution for 2x^2+10x-25/4x+28 equation: 


x in (-oo:+oo)

2*x^2+10*x-((25/4)*x)+28 = 0

2*x^2+10*x+(-25/4)*x+28 = 0

2*x^2+15/4*x+28 = 0

DELTA = (15/4)^2-(2*4*28)

DELTA = -3359/16

DELTA < 0

x belongs to the empty set

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